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		<title>An introduction to binary &#8211; Part 2</title>
		<link>http://leonardopires.wordpress.com/2008/10/14/an-introduction-to-binary-part-2/</link>
		<comments>http://leonardopires.wordpress.com/2008/10/14/an-introduction-to-binary-part-2/#comments</comments>
		<pubDate>Tue, 14 Oct 2008 16:19:18 +0000</pubDate>
		<dc:creator>leonardopires</dc:creator>
				<category><![CDATA[Computer Science]]></category>
		<category><![CDATA[Binary]]></category>
		<category><![CDATA[English]]></category>
		<category><![CDATA[Math]]></category>

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		<description><![CDATA[* This post is a continuation for: An introduction to binary &#8211; Part 1 Continuing our introduction to binary, let&#8217;s think about how could we express numbers using an alphabet with only 2 elements: The first two numbers are quite obvious: But how can we go any further? Well, in decimal, when our alphabet is not [...]<img alt="" border="0" src="http://stats.wordpress.com/b.gif?host=leonardopires.wordpress.com&amp;blog=4991269&amp;post=105&amp;subd=leonardopires&amp;ref=&amp;feed=1" width="1" height="1" />]]></description>
			<content:encoded><![CDATA[<p>* This post is a continuation for: <a title="Read An introduction to binary - Part 1" rel="bookmark" href="http://leonardopires.net/2008/10/10/an-introduction-to-binary-part-1/">An introduction to binary &#8211; Part 1</a></p>
<p>Continuing our introduction to binary, let&#8217;s think about how could we express numbers using an alphabet with only 2 elements:</p>
<p><img src="http://www.codecogs.com/eq.latex?B=%5C%7B0,1%5C%7D" alt="" width="75" height="17" /></p>
<p>The first two numbers are quite obvious:</p>
<p><img src="http://www.codecogs.com/eq.latex?0, 1" alt="" width="23" height="14" /></p>
<p>But how can we go any further? Well, in decimal, when our alphabet is not enough to write a number, we increment the leftmost number and &#8220;reset&#8221; any number on its right side; so: <img src='http://s0.wp.com/latex.php?latex=00%2C+01%2C+...%2C+09%2C+10%2C+..%2C+19%2C+20%2C+...%2C+099%2C+100%2C+...%2C+199%2C+200%2C+...+&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='00, 01, ..., 09, 10, .., 19, 20, ..., 099, 100, ..., 199, 200, ... ' title='00, 01, ..., 09, 10, .., 19, 20, ..., 099, 100, ..., 199, 200, ... ' class='latex' /></p>
<p>In binary we just do the same:</p>
<p><img src='http://s0.wp.com/latex.php?latex=00%2C+01%2C+10%2C+11%2C+100%2C+101%2C+110%2C+111%2C+1000%2C+...+&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='00, 01, 10, 11, 100, 101, 110, 111, 1000, ... ' title='00, 01, 10, 11, 100, 101, 110, 111, 1000, ... ' class='latex' /></p>
<p>If it&#8217;s not clear enough, think about the numbers as a car&#8217;s <a href="http://auto.howstuffworks.com/odometer1.htm" target="_blank">odometer (click to learn more about it)</a>:</p>
<p><a class="image" title="Odometer rollover" href="http://en.wikipedia.org/wiki/Image:Odometer_rollover.jpg"><img src="http://static.howstuffworks.com/gif/odometer2.jpg" alt="" /></a></p>
<p>When a digit reaches 9 then it becomes 0 and the next digit is incremented. If you bring this to the binary world, when a digit reaches 1, it becomes 0 and the next digit is incremented.</p>
<p>So, we might say that:</p>
<p><img src='http://s0.wp.com/latex.php?latex=00000+%3D+0%2C+%5C%5C+00001+%3D+1%2C+%5C%5C+00010+%3D+2%2C+%5C%5C+00011%3D+3%2C+%5C%5C+00100+%3D+4%2C+%5C%5C+00101+%3D+5%2C+%5C%5C+00110+%3D+6%2C+%5C%5C+00111+%3D+7%2C+%5C%5C+01000+%3D+8%2C+%5C%5C+01001+%3D+9%2C+%5C%5C+01010+%3D+10%2C+%5C%5C+01011+%3D+11%2C+%5C%5C+01100+%3D+12%2C%5C%5C+01101+%3D+13%2C+%5C%5C+01110+%3D+14%2C+%5C%5C+01111+%3D+15%2C+%5C%5C+10000+%3D+16...+&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='00000 = 0, &#92;&#92; 00001 = 1, &#92;&#92; 00010 = 2, &#92;&#92; 00011= 3, &#92;&#92; 00100 = 4, &#92;&#92; 00101 = 5, &#92;&#92; 00110 = 6, &#92;&#92; 00111 = 7, &#92;&#92; 01000 = 8, &#92;&#92; 01001 = 9, &#92;&#92; 01010 = 10, &#92;&#92; 01011 = 11, &#92;&#92; 01100 = 12,&#92;&#92; 01101 = 13, &#92;&#92; 01110 = 14, &#92;&#92; 01111 = 15, &#92;&#92; 10000 = 16... ' title='00000 = 0, &#92;&#92; 00001 = 1, &#92;&#92; 00010 = 2, &#92;&#92; 00011= 3, &#92;&#92; 00100 = 4, &#92;&#92; 00101 = 5, &#92;&#92; 00110 = 6, &#92;&#92; 00111 = 7, &#92;&#92; 01000 = 8, &#92;&#92; 01001 = 9, &#92;&#92; 01010 = 10, &#92;&#92; 01011 = 11, &#92;&#92; 01100 = 12,&#92;&#92; 01101 = 13, &#92;&#92; 01110 = 14, &#92;&#92; 01111 = 15, &#92;&#92; 10000 = 16... ' class='latex' /></p>
<p>Looking at those numbers, we can find a pattern: some of them have only one &#8220;1&#8243; and some zeros: 1, 10, 100, 1000, 10000. If we look at their values, we&#8217;ll be able to notice that they are, respecively, 1, 2, 4, 8 and 16. All those numbers are powers of 2:</p>
<p><img src="http://www.codecogs.com/eq.latex?1 = 1 = 1 \times 2^0, 10 = 2 = 1 \times 2^1, 100 = 4= 1 \times 2^2," alt="" width="352" height="18" /></p>
<p><img src="http://www.codecogs.com/eq.latex?1000 = 8= 1 \times 2^3, 10000 = 16=1 \times 2^4, ..." alt="" width="298" height="18" /></p>
<p>What if we replace the number 2 from the base of the multipliers for its binary notation?</p>
<p><img src="http://www.codecogs.com/eq.latex?1 = 1 = 1 \times 10^0, 2 = 10 = 1 \times 10^1, 4 = 100 = 1 \times 10^2," alt="" width="376" height="18" /></p>
<p><img src="http://www.codecogs.com/eq.latex?8 = 1000 = 1 \times 10^3, 16= 10000 = 1 \times 10^4, ..." alt="" width="315" height="18" /></p>
<p>To represent other numbers, we can work in an analogue fashion:</p>
<p><img src="http://www.codecogs.com/eq.latex?110 = 100 + 10+ 0 = 1 \times 10 ^ 2 + 1 \times 10 ^1 + 0 \times 10 ^ 1 \Rightarrow" alt="" width="371" height="16" /></p>
<p><img src="http://www.codecogs.com/eq.latex?110 = 100 + 10+ 0 = 1 \times 2 ^ 2 + 1 \times 2 ^1 + 0 \times 2 ^ 1 \Rightarrow" alt="" width="346" height="16" /></p>
<p><img src="http://www.codecogs.com/eq.latex?110 = 100 + 10+ 0 = 4 + 2 + 0 = 6" alt="" width="251" height="12" /></p>
<p>In other words: binary is just the same as decimal!</p>
<p>If we generalize the concept, we might say that:</p>
<p><img src="http://www.codecogs.com/eq.latex?(110)_{10}=1\times10^2 + 1\times10^1 + 0\times10^0 \wedge" alt="" width="276" height="19" /></p>
<p><img src="http://www.codecogs.com/eq.latex?(110)_{2}=1\times2^2 + 1\times2^1 + 0\times2^0 \Rightarrow" alt="" width="255" height="19" /></p>
<p><img src="http://www.codecogs.com/eq.latex?(110)_{b}=1\times b^2 + 1\times b^1 + 0\times b^0" alt="" width="229" height="19" /></p>
<p>Do I need to explain how to proceed for base 8 (octal) and base 16 (hexadecimal)?</p>
<p>Stay tuned and wait for An introduction to binary &#8211; Part 3 (I didn&#8217;t know how to sum).</p>
<p>* This post is a continuation for: <a title="Read An introduction to binary - Part 1" rel="bookmark" href="http://leonardopires.net/2008/10/10/an-introduction-to-binary-part-1/">An introduction to binary &#8211; Part 1</a></p>
<p><a href="http://www.codecogs.com/"><img title="CodeCogs - An Open Source Numerical Library" src="http://www.codecogs.com/images/poweredbycc.gif" border="0" alt="CodeCogs - An Open Source Numerical Library" /></a></p>
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			<media:title type="html">LeonardoPires</media:title>
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			<media:title type="html">CodeCogs - An Open Source Numerical Library</media:title>
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	</item>
		<item>
		<title>An introduction to binary &#8211; Part 1</title>
		<link>http://leonardopires.wordpress.com/2008/10/10/an-introduction-to-binary-part-1/</link>
		<comments>http://leonardopires.wordpress.com/2008/10/10/an-introduction-to-binary-part-1/#comments</comments>
		<pubDate>Fri, 10 Oct 2008 17:25:43 +0000</pubDate>
		<dc:creator>leonardopires</dc:creator>
				<category><![CDATA[Computer Science]]></category>
		<category><![CDATA[Binary]]></category>
		<category><![CDATA[English]]></category>
		<category><![CDATA[Math]]></category>

		<guid isPermaLink="false">http://leonardopires.wordpress.com/?p=89</guid>
		<description><![CDATA[Decimal revisited: Before you start to understand binary numbers, you must first understand the decimal numbering system: Let&#8217;s start from a very simple number: What does that number mean? Well, we may say that: or Considering that (for those that are not familiar with logic, the &#8220;upside down V&#8221; means &#8220;AND&#8221;, and the arrow means [...]<img alt="" border="0" src="http://stats.wordpress.com/b.gif?host=leonardopires.wordpress.com&amp;blog=4991269&amp;post=89&amp;subd=leonardopires&amp;ref=&amp;feed=1" width="1" height="1" />]]></description>
			<content:encoded><![CDATA[<p><strong>Decimal revisited:</strong></p>
<p>Before you start to understand binary numbers, you must first understand the decimal numbering system:</p>
<p>Let&#8217;s start from a very simple number: <img src="http://www.codecogs.com/eq.latex?123" alt="" /></p>
<p>What does that number mean? Well, we may say that:</p>
<p><img src='http://s0.wp.com/latex.php?latex=123+%3D+100+%2B+20+%2B+3&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='123 = 100 + 20 + 3' title='123 = 100 + 20 + 3' class='latex' /></p>
<p>or</p>
<p><img src='http://s0.wp.com/latex.php?latex=123%3D%281+%5Ctimes+100+%2B+%282+%5Ctimes+10%29+%2B+%283+%5Ctimes+1%29&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='123=(1 &#92;times 100 + (2 &#92;times 10) + (3 &#92;times 1)' title='123=(1 &#92;times 100 + (2 &#92;times 10) + (3 &#92;times 1)' class='latex' /></p>
<p>Considering that (for those that are not familiar with logic, the &#8220;upside down V&#8221; means &#8220;AND&#8221;, and the arrow means &#8220;IT IMPLIES THAT&#8221;):</p>
<p><img src='http://s0.wp.com/latex.php?latex=%28100+%3D+10+%5E+2+%5Cwedge+10+%3D+10+%5E+1+%5Cwedge+1+%3D+10%5E0%29+%5CRightarrow+%5C%5C+%28123%3D%281+%5Ctimes+10%5E2%29+%2B+%282+%5Ctimes+10%5E1%29+%2B+%283+%5Ctimes+10%5E0%29%29+&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='(100 = 10 ^ 2 &#92;wedge 10 = 10 ^ 1 &#92;wedge 1 = 10^0) &#92;Rightarrow &#92;&#92; (123=(1 &#92;times 10^2) + (2 &#92;times 10^1) + (3 &#92;times 10^0)) ' title='(100 = 10 ^ 2 &#92;wedge 10 = 10 ^ 1 &#92;wedge 1 = 10^0) &#92;Rightarrow &#92;&#92; (123=(1 &#92;times 10^2) + (2 &#92;times 10^1) + (3 &#92;times 10^0)) ' class='latex' /></p>
<p>So, we can say that:</p>
<p><img src="http://www.codecogs.com/eq.latex?1258 = 1000 + 200 + 50 + 8 \Rightarrow" alt="" width="216" height="12" /></p>
<p><img src="http://www.codecogs.com/eq.latex? [1258=(1 \times 10^3 + (2 \times 10^2) + (5 \times 10^1) + (8 \times 10^0)]" alt="" width="370" height="19" /></p>
<p>Now we can see a pattern here: considering that the rightmost digit in our number is called the less significant and the leftmost is the most significant, we might say that the most significant digit has the exponent 0 and as the digits become more significant, the exponent is incremented. From now on, we&#8217;ll call as <em>n</em> the position of a digit, starting from the less significant digit.</p>
<p><strong>Digits x Alphabets:</strong></p>
<p>Now the question is: why are all the digits multiplied by <img src="http://www.codecogs.com/eq.latex?10^n" alt="" width="22" height="12" /> ?</p>
<p>Let&#8217;s go back to basics:</p>
<p>We can express any integer number in the decimal system using the &#8220;alphabet&#8221; defined on this set:</p>
<p><img src="http://www.codecogs.com/eq.latex?D=\{0,1,2,3,4,5,6,7,8,9\}" alt="" width="199" height="17" /></p>
<p>And, if you have half a brain, you&#8217;ll be able to count and notice that we have 10 (TEN) digits on this set. So, we say that the <em>base</em> of the decimal system is the number 10 (TEN).</p>
<p>If we dig a bit deeper, we can understand why the numeral &#8220;10&#8243; represents the number TEN:</p>
<p>Using just one digit, we are able to represent the following numbers:</p>
<p><img src="http://www.codecogs.com/eq.latex?0,1,2,3,4,5,6,7,8,9" alt="" width="147" height="14" /></p>
<p>How do we represent the next number?</p>
<p>Well, consider that 9 can be represented as 09, what we do is just increment the leftmost number and &#8220;reset&#8221; everything on its right:</p>
<p><img src="http://www.codecogs.com/eq.latex?09 + 01 = 10 \Rightarrow 099 + 001 = 100 \Rightarrow 0999 + 0001 = 1000 \cdots" alt="" width="419" height="12" /></p>
<p><strong>First thoughts about binary:</strong></p>
<p>Now that we understand about the decimal system, just wonder how could we represent integer numbers using an alphabet with only two digits (BInary has the prefix BI, that means 2) defined as:</p>
<p><img src="http://www.codecogs.com/eq.latex?B=\{0,1\}" alt="" width="75" height="17" /></p>
<p>Just a tip:</p>
<p><img src="http://www.codecogs.com/eq.latex?01 + 01 = 10 \Rightarrow 011 + 001 = 100 \Rightarrow 0111 + 0001 = 1000 \cdots" alt="" width="419" height="12" /></p>
<p>Want to know more? See <a title="Read An introduction to binary - Part 2" rel="bookmark" href="http://leonardopires.net/2008/10/14/an-introduction-to-binary-part-2/">An introduction to binary &#8211; Part 2</a></p>
<p>&#8211;</p>
<p><a href="http://www.codecogs.com"><img title="CodeCogs - An Open Source Numerical Library" src="http://www.codecogs.com/images/poweredbycc.gif" border="0" alt="CodeCogs - An Open Source Numerical Library" /></a></p>
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			<media:title type="html">LeonardoPires</media:title>
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			<media:title type="html">CodeCogs - An Open Source Numerical Library</media:title>
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